Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 9 - Systems of Differential Equations - 9.2 Vector Formulation - True-False Review - Page 592: b

Answer

False

Work Step by Step

To prove the statement, we obtain: $x_1(t)=\begin{bmatrix} x_{11}(t)\\ x_{12}(t) \end{bmatrix}$ and $x_2(t)=\begin{bmatrix} x_{21}(t)\\ x_{22}(t) \end{bmatrix}$ then we have: $$W_{[x_1,x_2]}(t)=\begin{bmatrix} x_{11}(t) & x_{21}(t)\\ x_{12}(t) & x_{22}(t) \end{bmatrix}\\ =x_{11}(t)x_{22}(t)-x_{12}(t)x_{22}(t)$$ $$W_{[x_2,x_1]}(t)=\begin{bmatrix} x_{21}(t) & x_{11}(t)\\ x_{22}(t) & x_{12}(t) \end{bmatrix}\\ =x_{21}(t) x_{12}(t) -x_{22}(t) x_{11}(t) \\ =-[x_{11}(t) x_{22}(t)-x_{12}(t) x_{21}(t) ] $$ Hence, we can see that $W_{[x_2,x_1]}(t)=-W_{[x_1,x_2]}(t)$
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