Chapter 9 - Systems of Differential Equations - 9.10 Nonlinear Systems - True-False Review - Page 662: e

False

The equilibrium point of the linear system arising from the Van der Pol Equation $\frac{d^2y}{dt^2}+3(y^2-1)\frac{dy}{dt}=0$ is $\mu=3$. But from the textbook, it has been stated that if $\mu \geq 2$, the equilibrium point is an unstable node, not an unstable spiral.