Answer
False
Work Step by Step
The variation-of-parameters method seeks a particular solution of the form
$y_p(x) = u_1(x)y_1(x)+u_2(x)y_2(x)+· · ·+u_n(x)y_n(x)$
where $y_1,y_2,...y_n$ should form a linearly independent set of solutions.
Hence, the statement is not true.