Answer
True
Work Step by Step
For the steady state , the current is maximum when
$\omega^2=\dfrac{1}{LC} \implies \omega_{max}=\dfrac{1}{\sqrt {LC}}$
Therefore, the given statement is $\bf{True}$.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 8 - Linear Differential Equations of Order n - 8.6 RLC Circuits - True-False Review - Page 546: c
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