Answer
False.
Work Step by Step
An $n × n$ matrix is non-defective if and only if it has $n$ linearly independent eigenvectors. Thus the statement is false.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 7 - Eigenvalues and Eigenvectors - 7.2 General Results for Eigenvalues and Eigenvectors - True-False Review - Page 451: a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
