Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.5 Chapter Review - Additional Problems - Page 377: 7

Answer

$(1,0,0),(0,1,0),(0,0,1)$

Work Step by Step

We are given: $x_1=(6,-3,2)\\ x_2=(1,1,1)\\ x_3=(1,-8,1)$ in $R^3$ We need to check whether $x_1$ and $x_2$ are linearly independent. Obtain the matrices: $\begin{bmatrix} 6 & -3 & 2\\ 1 & 1 & 1 \\ 1 & -8 &1 \end{bmatrix} \approx \begin{bmatrix} 1 & 1 & 1\\ 6 & -3 & 2 \\ 1 & -8 &1 \end{bmatrix} \approx \begin{bmatrix} 1 & 1 & 1\\ 0 & -9 & -4 \\ 0& -9 & 0 \end{bmatrix} \approx \begin{bmatrix} 1 & 1 & 1\\ 0 & 0 & -4 \\ 0& 1 & 0 \end{bmatrix} \approx \begin{bmatrix} 1 & 0 & 1\\ 0 & 0 & 1 \\ 0& 1 & 0 \end{bmatrix} \approx \begin{bmatrix} 1 & 0 & 1\\ 0 & 1 & 0 \\ 0& 0 & 1 \end{bmatrix} \approx \begin{bmatrix} 1 & 0 & 0\\ 0 & 1 & 0 \\ 0& 0 & 1 \end{bmatrix}$ Hence, $x_1, x_2$ and $x_3$ are linearly independent vectors. Consequently, $(1,0,0),(0,1,0),(0,0,1)$ are also orthogonal vectors. Hence, a corresponding orthogonal basic for span $S$ is: $(1,0,0),(0,1,0),(0,0,1)$
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