Answer
1. $\vec{v}_1$=(-3,-12)
2. $\vec{v}_2$=(20,-4)
3. $\vec{v}_3$=(17,-16)
Work Step by Step
Steps:
1. Subtitute the components of the geometric $\vec{x}$ into the equation of $\vec{v}_1$. Then, each components of the geometric $\vec{v}_1$ is times with 3.
$\vec{v}_1$= 3$\vec{x}$ = 3(-1,-4)=(-3,-12)
2. Subtitute the components of the geometric $\vec{y}$ into the equation of $\vec{v}_2$. Then, each components of the geometric $\vec{v}_2$ is times with -4.
$\vec{v}_2$= -4$\vec{y}$ = -4(-5,1)=(20,-4)
3. $\vec{v}_3$ is the summation of $\vec{v}_1$ and $\vec{v}_2$. Therefore, using the previous answers, replaced $\vec{v}_3$ by
$\vec{v}_3$= $\vec{v}_1$+ $\vec{v}_2$ = (-3,-12)+(20,-4)=(17,-16).
