Answer
True.
Work Step by Step
True because if $rv=sv$, then $rv-sv=(r-s)v=0$, thus either $v=0$ (which here cannot be the case, or $r-s=0$ which is the same as $r=s$.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 4 - Vector Spaces - 4.2 Definition of Vector Spaces - True-False Review - Page 262: c
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