Answer
False
Work Step by Step
From the given form of matrix, we obtain $\begin{bmatrix}
1 & 2 & 1\\3 & 6 & 2 \\ 1& 0 & 0
\end{bmatrix}$. We can see that this matrix is invertible.
Hence, the statement is false.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 4 - Vector Spaces - 4.10 Invertible Matrix Theorem II - True-False Review - Page 332: j
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