Answer
See answer below
Work Step by Step
Let $A$ and $B$ are invertible $n × n$ matrices
By part (e) in the Invertible Matrix Theorem, we have:
$$A=E_1E_2$$
$$B=E_3E_4$$
$E_k$ with $k=1,2,3,4...$ are elementary matrices
So $$AB=E_1 E_2 E_3 E_4$$ is a product of elementary matrices too
Since $E_k$ are invertible (by part a in the Invertible Matrix Theorem), $AB$ is vertible too (by Theorem 2.6.10)