Answer
a) $b_{12}=-1$
$b_{33}=4$
$b_{41}=0$
$b_{43}=8$
$b_{51}=-1$
$b_{52}=9$
b) $(1,3); (1,2);(2,1); (3,2)$ and $(5,1)$
Work Step by Step
a) $b_{12}$ is the element lying in the 1st row and 2nd column and it is equal to $-1$
Similarly we can find the values of all the other elements.
b) Entry lying in the $1^{st}$ row and $3^{rd}$ column
= Entry lying in the $1^{st}$ row and $2^{nd}$ column
= Entry lying in the $2^{nd}$ row and $1^{st}$ column
= Entry lying in the $3^{rd}$ row and $2^{nd}$ column
= Entry lying in the $5^{th}$ row and $1^{st}$ column
= -1.
So, the pairs are $(1,3); (1,2);(2,1); (3,2)$ and $(5,1)$.
