Answer
True
Work Step by Step
The second shifting theorem states that $L {f(t) \cdot u (t-a) }= e^{-as} L { f(t+a) }$.
The correct form of the given statement is:
$L^{-1} (\dfrac{e^3}{s^2+9}) =L^{-1} [ \dfrac{e^s}{3} L (\sin (3t))]$.
Therefore, the given statement is $\bf{True}$.
