Answer
False
Work Step by Step
Let us consider an example:
$f(x)=g(x)=1$ and $f(x-3)=1=g(x)$
Now, $\int_0^1 f(t) \ dt =1$ and $\int_0^1 g(t) \ dt =1$
This implies that the equality is not correct because $1\ne 1-3$
Therefore, the given statement is $\bf{False}$.