Answer
See below
Work Step by Step
Since, $y(s)=\dfrac{2}{s+1} +\dfrac{3}{(s+1)^2}+\dfrac{2}{(s+1)^3}$
The inverse Laplace transform of function can be expressed as:
$y(t)=\dfrac{2}{s+1} +\dfrac{3}{(s+1)^2}+\dfrac{2}{(s+1)^3}$
Now, apply the first shifting Theorem.
$f(t)= 2e^{-t} +3te^{-t} +t^2e^{-t} $