Answer
True
Work Step by Step
The given statement is correct. Because we can solve easily differential equations by boundary or initial values or points as arbitrary constants.
Therefore, the given statement is $\bf{True}$.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.4 The Transform of Derivatives and Solution of Initial-Value Problems - True-False Review - Page 689: c
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