Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.2 The Existence of the Laplace Transform and the Inverse Transform - True-False Review - Page 685: h

Answer

False

Work Step by Step

We must know that the Laplace transform of a periodic function can never be periodic. This implies that the given function $\dfrac{1}{(s^2+1)(1-e^{-\pi s})}$ represents a decreasing function, thus it cannot be considered as a periodic function. Therefore, the given statement is $\bf{False}$.
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