Answer
True
Work Step by Step
Multiply both sides by $e^{p(x)dx}$ we have:
$\frac{d}{dx}(ye^{\int p(x)dx})\\=e^{\int p(x)dx}y'+p(x)e^{\int p(x)dx}\\=e^{\int p(x)dx}q(x)dx\\=\frac{d}{dx}(\int e^{\int p(x)dx}q(x)dx)$
We can notice that by multiplying by $e^{p(x)dx}$ gives us integrate differential equation. Hence, $e^{\int p(x)dx}q(x)dx$ is integrating factor.
