Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 1 - First-Order Differential Equations - 1.1 Differential Equations Everywhere - Problems - Page 12: 24

Answer

$t=4.5175$ $s$

Work Step by Step

According to question: $\frac{d^{2}y}{dt^{2}}=g$, $y(0)=0$, $\frac{dy}{dt}(0)=0$ On integration, $\frac{dy}{dt}=gt+c_1$ Using inital condition put $t=0$ and $\frac{dy}{dt}(0)=0$ $0=g\cdot0+c_1$ $c_1=0$ $\frac{dy}{dt}=gt$ On integrating again, $y=\frac{1}{2}gt^2+c_2$ Using intial condition $y(0)=0$, $0=\frac{1}{2}g\cdot(0)^2+c_2$ $c_2=0$ So equation becomes $y=\frac{1}{2}gt^2$ Put $y=100$ $m$ and $g=9.8$ ${m}{s^{-2}}$ $100=\frac{1}{2}(9.8)(t^2)$ $t=\sqrt{20.4081}$ $s$$=4.5175$ $s$
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