## Differential Equations and Linear Algebra (4th Edition)

Lets determine the right hand side of the equation first (RHS). $y^{'}$ = 1/t $y^{''}$ = -1/$t^{2}$ $y^{'''}$ = 2/$t^{3}$ = RHS Now lets determine the left hand side of the equation (LHS). 2$(y^{'})^{3}$ = 2($(1/t)^{3}$ = 2/$t^{3}$ = LHS As LHS = RHS, the equation is satisfied.