College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 9

Answer

(a) yes (b) no

Work Step by Step

(a) Using $x=2$, we get: Left side: $1-[2-(3-2)]=1-[2-1]=1-1=0$ and RHS $=4(2)-(6+(2))=8-8=0$ Right side: $4(2)-(6+2)=8-8=0$ The sides match, so $x=2$ is a solution. (b) Using $x=4$, we get: Left side: $1-[2-(3-4)]=1-[2-(-1)]=1-3=-2$ Right side: $4(4)-(6+4)=16-10=6$ The sides do not match, so $x=4$ is not a solution.
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