Answer
$x^2+y^2\gt 4$
Work Step by Step
According to the given graph and the equation, our inequality is:
$x^2+y^2\gt 4$.
This includes the shaded area but not the function itself (because we do not have an equals sign). Notice that we used a greater-than sign to shade the graph outside the circle.
We confirm the inequality by plugging in $(0,0)$, which gives us:
$0^2+0^2\geq4$
This is a false statement as expected since $(0,0)$ is not in the shaded area. Therefore, the inequality works.
