College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2: 117

Answer

$=(1.0568 \times 10^4)$ dollars

Work Step by Step

The exercise asks us to find the total money earned in 2010. This means that we must multiply the amount of tickets sold by their average price. Since the exercise asks us to use scientific notation, however, we'll comply by first converting both variables to scientific notation: Tickets sold: $1,340 = (1.34 \times 10^3)$ Ticket price: $ 7.90 = (7.90 \times 10^0)$ Now, we simply use the commutative property of multiplication with both expressions to achieve the answer: $$(1.34 \times 10^3) \times (7.90 \times 10^0)$$ $$=$$ $$(1.34 \times 7.90) \times (10^3 \times 10^0)$$ $= (10.586) \times (10^{3 + 0} = 10^3)$ $=(1.0568 \times 10^1) \times (10^3)$ $=(1.0568) \times (10^3\times10^1 = 10^{3+1} = 10^4)$ $=1.0568 \times 10^4$
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