# Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2 - Page 33: 46

$=99x^{17}$

#### Work Step by Step

When multiplying two exponential expressions, group factors with the same base: $$(11x^{5})(9x^{12})$$ $$=(11\times9)(x^{5}\times x^{12})$$ $$=99x^{(5+12)}$$ $$=99x^{17}$$

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