Answer
$=99x^{17}$
Work Step by Step
When multiplying two exponential expressions, group factors with the same base: $$(11x^{5})(9x^{12})$$
$$=(11\times9)(x^{5}\times x^{12})$$
$$=99x^{(5+12)}$$
$$=99x^{17}$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2 - Page 33: 46
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