College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.1 - Page 19: 132

Answer

a.) $T=25,004$ b.) $139$

Work Step by Step

a.) Given $T=26x^2+819x+15,527$ and $x=9$, substituting $x$ we have: $T=26\times(9)^2+819\times 9+15,527$ $T=26\times 81+819\times 9+15,527$ $T=2,106+7,371+15,527$ $T=25,004$ b.) $25,143-25,004=y$ $25,143-25,004=139$
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