## College Algebra (6th Edition)

The age is known, so plug the age into the given equation for the lower limit of the range. a. $\frac{1}{2}\times(220-30) = \frac{1}{2}\times190$ $=95$ Using the same method as before, plug the age into the equation for the upper limit of the range. b. $\frac{3}{5}\times(220-30) = \frac{3}{5}\times190$ $=114$