College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.1 - Page 17: 14



Work Step by Step

$\frac{7(x-3)}{2x-16}$ for $x=9$ substitute 9 for each x $=\frac{7(9-3)}{2(9)-16}$ complete any grouped operations first - remember that the numerator and denominator of a fraction are each considered grouped $=\frac{7\times6}{18-16}$ within each group, first complete multiplication and division in order left to right, then addition and subtraction left to right $\frac{42}{2}$ finish with division - fractions mean divide the numerator by the denominator $=21$
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