Answer
Factors of the first denominator = (x+3)(x-2)
Factors of the second denominator = (x+3)(x+1)
The LCD = (x+3)(x-2)(x+1)
Work Step by Step
$x^{2}+x-6$ factored out is (x+3)(x-2)
$x^{2}+4x+3$ factored out is (x+3)(x+1)
(x+3) is common in both denominators. The remaining denoimnators are (x-2) and (x+1); Therefore, the LCD is (x+3)(x-2)(x+1)
