College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Concept and Vocabulary Check - Page 48: 7


$5$, then $6\sqrt3$

Work Step by Step

$\sqrt3 + \sqrt {75}$ Split 75 into two factors such that one is a perfect square: $=\sqrt3 + \sqrt {25\cdot3}$ (not shown: $=\sqrt3 + \sqrt {25}\sqrt3$) $=\sqrt3 + 5\sqrt3$ (not shown: $=1\sqrt3 +5\sqrt3 = (1+5)\sqrt3$) $=6\sqrt3$
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