College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Concept and Vocabulary Check - Page 32: 7



Work Step by Step

This problem tests how you deal with negative exponents in numerators and denominators. According to the instructions given in the textbook, When a negative number appears as an exponent,switch the position of the base (from the numerator to the denominator or from the denominator to the numerator) and make the exponent positive. The sign of the base does not change. In the given case, $\frac{1}{8^{-2}}=\frac{8^2}{1}=8^2$.
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