## College Algebra (6th Edition)

a. $|1-\sqrt 2|$ =$-(1-\sqrt 2)$ = $\sqrt 2 - 1$ b. $|\pi-3|$ = $\pi-3$ c. $|x|/x$ = 1
a. The number inside the absolute value bars, $|1-\sqrt 2|$ , is negative. Because $\sqrt 2$ $\approx$ 1.414.$(1-1.414)$ = -0.414. The absolute value of negative number is negative. Thus $|1-\sqrt 2|$ =$-(1-\sqrt 2)$ =$\sqrt 2 - 1$ b. The number inside the absolute value bars is positive. Because $\pi\approx3.14$. Thus |3.14 - 3| $\gt$ 0. The absolute value of a positive number is the number itself. So, $|\pi-3|$ = $\pi-3$ c. If x$\gt$0, then $|x|$ = x. Thus, $|x|/x$ = $x/x$ = 1