College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 792: 30

Answer

$\frac{1}{16}$

Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ The events are independent, so we can find the probability of both of them happening by finding the probability of them happening individually and multiplying those. The probability of the first event: $\frac{2}{8}=\frac{1}{4}$, the probability of the first event: $\frac{2}{8}=\frac{1}{4}$, thus the probability of both of them happening is: $\frac{1}{4}\frac{1}{4}=\frac{1}{16}$
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