## College Algebra (6th Edition)

$20$
If we want to choose $k$ elements out of $n$ disregarding the order, not allowing repetition, we can do this in $_{n}C_k=\frac{n!}{(n-k)!k!}$ ways. The order doesn't matter here when choosing the jokes, thus we have to use combinations. We choose $3$ out of $6$. Thus $_{6}C_{3}=\frac{6!}{(6-3)!3!}=20$