College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 742: 105

Answer

False.

Work Step by Step

In order for a sequence to be geometric, the quotient of all consecutive terms must be constant. Hence here: $\frac{a_2}{a_1}=\frac{6}{2}=3\ne4=\frac{24}{6}=\frac{a_3}{a_2}$, thus it is not a geometric sequence.
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