Answer
314628 is the $200^{th}$ term of the sequence 21700, 23172, 24644, 26116, . . . . .
Work Step by Step
Given sequence = 21700, 23172, 24644, 26116, . . . . .
Difference between 26116 and 24644 = 26116 -24644 = 1472
Difference between 24644 and 23172 = 24644 - 23172= 1472
Difference between 23172 and 21700 = 23172 - 21700 = 1472
Common difference = 1472
$1^{st}$ term $x_{1}$= 21700
Given Last term $x_{L}$ = 314628
Number of terms = $\frac{(x_{L} - x_{1})}{d}$ + 1
= $\frac{(314628 - 21700)}{1472}$ + 1
= $\frac{292928}{1472}$ + 1
= 199 + 1
= 200
314628 is the $200^{th}$ term of the sequence 21700, 23172, 24644, 26116, . . . . .
