College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-7) - Page 7074: 8

Answer

$x=\frac{-2}{3}$ $y=-1$

Work Step by Step

(1)$x = \frac{2}{3}-\frac{4}{3}y $ and (2) $2x + 5y=-1$ Use x in (1) for x in (2) we get $2(\frac{2}{3}-\frac{4}{3}y ) + 5y = -1$ $\frac{7}{3}y=-\frac{7}{3}$ $y=-1$ $x=\frac{2}{3}-\frac{4}{3}y=\frac{-2}{3}$
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