Answer
See graph
Work Step by Step
We are given the parabola:
$y=x^2+4x-5$
Bring the equation to the standard form:
$(x-h)^2=4p(y-k)$
$x^2+4x+4=y+9$
$(x+2)^2=y+9$
Determine $h,k,p$:
$h=-2$
$k=-9$
$4p=1\Rightarrow p=\dfrac{1}{4}$
Determine the vertex:
$V(h,k)=(-2,-9)$
Consider another points to help graphing the parabola:
$x=0\Rightarrow y=0^2+4(0)-5=-5$
$x=-4\Rightarrow y=(-4)^2+4(-4)-5=-5$
Plot the vertex and the additional points and sketch the parabola:
