College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.1 - Page 673: 85

Answer

$x^2+y^2=25$ $x^2+y^2=9$

Work Step by Step

We are given the circles: Circle 1: $r_1=5$ Center: $C_1(0,0)$ Circle 2: $r_2=3$ Center: $C_2(0,0)$ The standard equation of a circle is: $(x-h)^2+(y-k)^2=r^2$ For both circles we have: $h=0$ $k=0$ The equation of the first circle is: $x^2+y^2=r_1^2$ $x^2+y^2=5^2$ $x^2+y^2=25$ The equation of the second circle is: $x^2+y^2=r_2^2$ $x^2+y^2=3^2$ $x^2+y^2=9$
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