Answer
$(-3,0),(3,0)$
Work Step by Step
The ellipse is centred in the origin.
We are given:
$a^2=25$
$b^2=16$
Determine $a,b,c$:
$a^2=25\Rightarrow a=\sqrt{25}=5$
$b=16\Rightarrow b=\sqrt{16}=4$
$c^2=a^2-b^2$
$c^2=25-16$
$c^2=9$
$c=\pm\sqrt {9}=\pm 3$
The foci are:
$F_1(-c,0)=(-3,0)$
$F_2(c,0)=(3,0)$
Graph the ellipse:
