## College Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Conic Sections - Concept and Vocabulary Check - Page 684: 7

#### Answer

Fill the blanks with $... y=2x \ \ ... \ \ y=-2x$.

#### Work Step by Step

The hyperbola $\displaystyle \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1$ has a vertical transverse axis and two asymptotes $y=\displaystyle \frac{a}{b}x$ and $y=-\displaystyle \frac{a}{b}x$. ---------- $\displaystyle \frac{y^{2}}{2^{2}}-\frac{x^{2}}{1^{2}}=1$ $a=2, \quad b=1.$ The asymptotes are $y=2x$ and $y=-2x$. Fill the blanks with $... y=2x ... y=-2x$.

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