College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 653: 46

Answer

$x=26$

Work Step by Step

$\left|\begin{array}{ll} x+3 & -6\\ x-2 & -4 \end{array}\right|=(x+3)(-4)-(-6)(x-2)$ $=-4x-12+6x-12=2x-24$ $2x-24=28\qquad/+24$ $2x=52\qquad/\div 2$ $x=26$
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