College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 652: 12

Answer

Solution set = $\{(2,-1)\}$

Work Step by Step

$D= $determinant of the coefficient matrix $=\left|\begin{array}{ll} 2 & 1\\ 1 & -1 \end{array}\right|=2(-1)-1(1)=-3$ $D_{x}=$ in D, replace the x column with the constants column $= \left|\begin{array}{ll} 3 & 1\\ 3 & -1 \end{array}\right|=3(-1)-1(3)=-6$ $D_{y}=$ in D, replace the x column with the constants column $=\left|\begin{array}{ll} 2 & 3\\ 1 & 3 \end{array}\right|=6-3=3$ $x=\displaystyle \frac{D_{x}}{D}=\frac{-6}{-3}=3$ $y=\displaystyle \frac{D_{y}}{D}=\frac{3}{-3}=-1$ Solution set = $\{(2,-1)\}$
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