Answer
$a_{23}$= the element in row 2, column 3 = $-6$
a. $3\times 4$
b.
$a_{32} =\displaystyle \frac{1}{2}$
$a_{23}$= $-6$
Work Step by Step
A matrix of order $m\times n$ has $m$ rows and $n$ columns.
$a_{ij}$ is the element of the matrix in row i, column j.
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a.
the matrix has m = $3$ rows and n = $4$ columns, so
its order is $3\times 4$
b.
$a_{32}$= the element in row 3, column 2,$ =\displaystyle \frac{1}{2}$
$a_{23}$= the element in row 2, column 3 = $-6$
a. $3\times 4$
b.
$a_{32} =\displaystyle \frac{1}{2}$
$a_{23}$= $-6$