College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.2 - Page 611: 49

Answer

$8$

Work Step by Step

$\frac{1}{2}\cdot[8-(-8)]=\frac{1}{2}\cdot[8+8]=\frac{1}{2}\cdot16=8$
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