College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.1 - Page 602: 68

Answer

See below.

Work Step by Step

If $z=0$, then $x=12\cdot0+1=1,y=10\cdot0-1=-1$, thus the equations are: $3\cdot1-4\cdot-1+4\cdot0=3+4+0=7\\1-(-1)-2\cdot0=1+1+0=2\\2\cdot1-3\cdot(-1)+6\cdot0=2+3+0=5$ These are all satisfied, thus we showed what we had to.
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