College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Concept and Vocabulary Check - Page 609: 5

Answer

Fill the blanks with: $x-y+z=5$ $y-z=-3$ $z+3$ $8$ $\{(8, z+3,z)\}$

Work Step by Step

Interpreting the matrix, Equation 1:$ \qquad x-y+z=5$ Equation 2:$\qquad \quad y-z=-3$ Solving Eq.2, (add z to both sides) $y=z+3$ Substituting this into Eq.1: $x-(z+3)+z=5$ $x-3=5$ $x=8$ Solution set:$\quad\{(8, z+3,z)\}$
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