College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Concept and Vocabulary Check - Page 598: 2

Answer

Fill blanks with: ... 3 ... ... second ... ... $-2$ ... ... third ...

Work Step by Step

To obtain a zero in the position (2,1), (row 2, column 1, where the current element is $-3$) multiply the element 1 in row 1 by 3 and add it to -3 (in the second row). So, the first two blanks are filled with ... 3 ... ... second ... To obtain a zero in the position (3,1), (row 3, column 1, where the current element is $2$) multiply the element 1 in row 1 by $-2$ and add it to $2$ (in the third row). So, the last two blanks are filled with ... $-2$ ... ... third ...
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.