College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.6 - Page 582: 37

Answer

See below.

Work Step by Step

$z=5$, thus plugging this into the second equation: $y+2\cdot5=13\\y+10=13\\y=3$ Thus plugging these values into the first equation: $x+3+2\cdot5=19\\x+13=19\\x=6$ It is easy to solve it because we can start from the bottom plug the values in and get easily solvable equations.
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