College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.3 - Page 549: 1


$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$

Work Step by Step

see p.541. Decomposition with Distinct Linear Factors In the Denominator: Include one partial fraction with a constant numerator for each distinct linear factor in the denominator. --------------------- The denominator on the LHS has distinct linear factors, no repeating. The RHS will contain linear denominators and constant numerators Setup only: $\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$
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