Answer
$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$
Work Step by Step
see p.541. Decomposition with Distinct Linear Factors In the Denominator:
Include one partial fraction with a constant numerator for each distinct linear factor in the denominator.
---------------------
The denominator on the LHS has distinct linear factors, no repeating.
The RHS will contain linear denominators and constant numerators
Setup only:
$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$
