#### Answer

$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$

#### Work Step by Step

see p.541. Decomposition with Distinct Linear Factors In the Denominator:
Include one partial fraction with a constant numerator for each distinct linear factor in the denominator.
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The denominator on the LHS has distinct linear factors, no repeating.
The RHS will contain linear denominators and constant numerators
Setup only:
$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$