## College Algebra (6th Edition)

$\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$
see p.541. Decomposition with Distinct Linear Factors In the Denominator: Include one partial fraction with a constant numerator for each distinct linear factor in the denominator. --------------------- The denominator on the LHS has distinct linear factors, no repeating. The RHS will contain linear denominators and constant numerators Setup only: $\displaystyle \frac{11x-10}{(x-2)(x+1)}=\frac{A}{(x-2)}+\frac{B}{(x+1)}$