College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.2 - Page 538: 28

Answer

$y=x^2-9x+22$

Work Step by Step

We have to determine $a,b,c$ so that the graph of the function $y=ax^2+bx+c$ passes through the points $(2,8),(3,4),(4,2)$. Use the fact that each of the given points $(x,y)$ satisfies the equation $y=ax^2+bx+x$. We find the system: $\begin{cases} a(2)^2+b(2)+c=8\\ a(3)^2+b(3)+c=4\\ a(4)^2+b(4)+c=2 \end{cases}$ $\begin{cases} 4a+2b+c=8\\ 9a+3b+c=4\\ 16a+4b+c=2 \end{cases}$ We will use the addition method. Multiply Equation 1 by -1 and add it to Equation 2 and Equation 3 to eliminate $c$: $\begin{cases} 9a+3b+c-4a-2b-c=4-8\\ 16a+4b+c-4a-2b-c=2-8 \end{cases}$ $\begin{cases} 5a+b=-4\\ 12a+2b=-6 \end{cases}$ $\begin{cases} 5a+b=-4\\ 6a+b=-3 \end{cases}$ Multiply Equation 1 by -1 and add it to Equation 2 to eliminate $b$ and determine $a$: $\begin{cases} -5a-b=4\\ 6a+b=-3 \end{cases}$ $-5a-b+6a+b=4-3$ $a=1$ Determine $b$ using the equation $5a+b=-4$: $5(1)+b=-4$ $5+b=-4$ $b=-9$ Determine $c$ by substituting $a,b$ in Equation 1: $4a+2b+c=8$ $4(1)+2(-9)+c=8$ $-14+c=8$ $c=22$ The system's solution is: $(1,-9,22)$ The function is fully determined: $y=x^2-9x+22$
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