College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Concept and Vocabulary Check - Page 558: 5

Answer

See below.

Work Step by Step

Since $x^2$ has the same coefficients in both equations, we need to multiply the second one by $-1$, then we get: $(x^2+y^2)-(x^2-y)=13-7\\x^2+y=6$
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